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A student got twice as many sums wrong as he got right, if he attempted 48 sums in all, how many did he solve correctly?

  • a)
    12                 

  • b)
    16                   

  • c)
    18                 

  • d)
    24

Correct answer is option 'B'. Can you explain this answer?
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To solve this problem, let's assume the number of sums the student got right is x. According to the given information, the student got twice as many sums wrong as he got right. Therefore, the number of sums the student got wrong is 2x.

We are also given that the student attempted 48 sums in total. This means the number of sums the student got right plus the number of sums the student got wrong should be equal to 48.

So, we can write the equation as:

x + 2x = 48

Simplifying the equation, we get:

3x = 48

Dividing both sides of the equation by 3, we find:

x = 16

Therefore, the student solved 16 sums correctly.

Answer: Option B) 16
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