The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. ...
Given:
- The ratio of two numbers is 3:4
- The H.C.F. (Highest Common Factor) of the two numbers is 4.
Let's denote the two numbers as 3x and 4x, where x is a common multiplier.
Since the H.C.F. of the two numbers is given as 4, x must be 4 (because H.C.F. is the highest common factor, and 4 is the common factor here).
So, the two numbers are:
- First number = 3×4=12
- Second number = 4×4=16
Now, let's calculate the L.C.M. (Least Common Multiple) of 12 and 16.
Method:
The L.C.M. of two numbers can be calculated using the formula:
LCM×HCF=Product of the numbers
So,
The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. ...
Given, the ratio of two numbers is 3 : 4 and their H.C.F. is 4.
Let the two numbers be 3x and 4x, where x is a positive integer.
Their H.C.F. is 4, which means that 4 is a factor of both 3x and 4x. Therefore, x must be a multiple of 4.
Let x = 4k, where k is a positive integer.
Then, the two numbers are 3x = 3(4k) = 12k and 4x = 4(4k) = 16k.
Their L.C.M. is given by the product of the numbers divided by their H.C.F., i.e.,
L.C.M. = (12k x 16k)/4 = 48k^2
Since k is a positive integer, the L.C.M. is a multiple of 48.
Therefore, the correct answer is option D) 48.