A car takes 2 hours more a distance of 480 kmwhen its speed is reduced...
Problem:
A car takes 2 hours more to cover a distance of 480 km when its speed is reduced. Find its usual speed.
Solution:
Let's assume the usual speed of the car is 'x' km/h.
When the car is traveling at its usual speed, it takes 't' hours to cover the distance of 480 km.
When the car's speed is reduced, it takes 't+2' hours to cover the same distance of 480 km.
Calculating Time:
We know that time = distance / speed.
- At usual speed: t = 480 / x
- At reduced speed: t+2 = 480 / x
Equation:
Since the car takes 2 hours more at the reduced speed, we can set up the following equation:
t+2 = t + 2 hours
Substituting the values of 't' from the previous equations:
480 / x + 2 = 480 / x
Cross Multiplication:
To solve the equation, we can cross multiply:
480x = (480 / x) * (x + 2)
Simplifying:
Simplifying the equation further:
480x = 480 + 960
480x = 1440
Dividing:
Dividing both sides of the equation by 480:
x = 1440 / 480
x = 3
Conclusion:
The usual speed of the car is 3 km/h.
A car takes 2 hours more a distance of 480 kmwhen its speed is reduced...