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50.0kg of N2 (g) and 10.0kg of H2(g)are mixed to produce NH3(g). Calculate the amount of NH3(g) formed. Identify the limiting reagent in the production of NH3 in this situation?
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50.0kg of N2 (g) and 10.0kg of H2(g)are mixed to produce NH3(g). Calcu...
N2 + 3H2---> 2NH3

which means 28g of nitrogen reacts with 6g of hydrogen to give 34g of ammonia.

When 50kg of N reacts with H of x kg
So, x=6/28× 50.
× = 10.7 kg
Here, the limiting reagant is H2 as we have only 10 kg of it

If 6kg of H2 gives 34kg of NH3
Then, 10 kg of H2 gives = 34/6×10
=56.6 kg of NH3
Community Answer
50.0kg of N2 (g) and 10.0kg of H2(g)are mixed to produce NH3(g). Calcu...
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50.0kg of N2 (g) and 10.0kg of H2(g)are mixed to produce NH3(g). Calculate the amount of NH3(g) formed. Identify the limiting reagent in the production of NH3 in this situation?
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50.0kg of N2 (g) and 10.0kg of H2(g)are mixed to produce NH3(g). Calculate the amount of NH3(g) formed. Identify the limiting reagent in the production of NH3 in this situation? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about 50.0kg of N2 (g) and 10.0kg of H2(g)are mixed to produce NH3(g). Calculate the amount of NH3(g) formed. Identify the limiting reagent in the production of NH3 in this situation? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 50.0kg of N2 (g) and 10.0kg of H2(g)are mixed to produce NH3(g). Calculate the amount of NH3(g) formed. Identify the limiting reagent in the production of NH3 in this situation?.
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