The zeros of the quadratic polynomial x^{2} + ax + h, a,b > 0 are

- a)both positive
- b)both negative
- c)one positive one negative
- d)can’t say

Correct answer is option 'B'. Can you explain this answer?

Related Test: MCQ : Polynomials - 2

5 Answers

Aditya Raj Singh
answered
Apr 15, 2020

Let m and n be roots ;

then,

m+n=-a;---1

and

mÃ—n=b---2

from ---2

we know , negative Ã— negative=positive (b=mÃ—n).

postive Ã— positive =positive (b=mÃ—n).

from ---1

a can be negative ,if and only if both are negative

or either one is negative.

in both we see;

both negative as common.

HENCE BOTH THE ROOTS ARE NEGATIVE

then,

m+n=-a;---1

and

mÃ—n=b---2

from ---2

we know , negative Ã— negative=positive (b=mÃ—n).

postive Ã— positive =positive (b=mÃ—n).

from ---1

a can be negative ,if and only if both are negative

or either one is negative.

in both we see;

both negative as common.

HENCE BOTH THE ROOTS ARE NEGATIVE

Lakshya Sharan
answered
May 06, 2020

Let the roots of equation be m and n

then

m+n= -a

m*n= b

as per question a>0

so m+n< />

and b>0

m*n>0

to satisfy the equations both m and n must be negative

then

m+n= -a

m*n= b

as per question a>0

so m+n< />

and b>0

m*n>0

to satisfy the equations both m and n must be negative

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