ABCD is a cyclic trapezium with AB || DC and AB is diameter of the circle. If ∠CAB = 50° then ∠ADC is –

- a)40°
- b)70°
- c)140°
- d)150°

Correct answer is option 'C'. Can you explain this answer?

Related Test: SSC CHSL Mock Test -11

Knowledge Hub
answered
4 weeks ago

We can see from the figure that,

ΔABC is right angled triangle,

⇒ ∠ABC = 90° - ∠CAB = 90° - 50° = 40°

Now,

∵ ABCD is a cyclic quadrilateral,

Opposite angles are supplementary.

⇒ ∠ABC + ∠ADC = 180°

⇒ 40° + ∠ADC = 180°

⇒ ∠ADC = 140°

∴ ∠ADC = 140°

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