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A dihybrid cross is made between YYrr and yyRR. In F2 generation, the ratio of parental to recombinant phenotype is:
- a)9 : 7
- b)6 : 10
- c)10 : 6
- d)7 : 9
Correct answer is option 'C'. Can you explain this answer?
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A dihybrid cross is made between YYrr and yyRR. In F2 generation, the ...
Dihybrid cross between YYrr and yyRR:
- A dihybrid cross involves the inheritance of two different traits at the same time.
- In this case, the two traits are yellow (Y) vs. green (y) seed color and round (R) vs. wrinkled (r) seed texture.
- The parents are YYrr (homozygous dominant for seed color and homozygous recessive for seed texture) and yyRR (homozygous recessive for seed color and homozygous dominant for seed texture).
F1 generation:
- The F1 offspring will all be heterozygous for both traits (YyRr).
F2 generation:
- When the F1 offspring are allowed to self-fertilize, the resulting F2 generation will have a phenotypic ratio of 9:3:3:1.
- This ratio is derived from the four possible combinations of alleles from the two traits: YR, Yr, yR, and yr.
- The expected ratios for each phenotype are:
- Yellow and round (YyRr or YYRR or YYRr or YyRR): 9/16 or 56.25%
- Yellow and wrinkled (Yyrr or YYrr): 3/16 or 18.75%
- Green and round (yyRr or yyRR): 3/16 or 18.75%
- Green and wrinkled (yyrr): 1/16 or 6.25%
Ratio of parental to recombinant phenotype:
- Parental phenotypes are those that match the phenotypes of the parents (YYrr and yyRR).
- Recombinant phenotypes are those that have new combinations of traits not seen in the parents (Yyrr and yyRr).
- In this cross, the ratio of parental to recombinant phenotypes is 10:6 or simplified to 5:3, which is option C in the given choices.
- A dihybrid cross involves the inheritance of two different traits at the same time.
- In this case, the two traits are yellow (Y) vs. green (y) seed color and round (R) vs. wrinkled (r) seed texture.
- The parents are YYrr (homozygous dominant for seed color and homozygous recessive for seed texture) and yyRR (homozygous recessive for seed color and homozygous dominant for seed texture).
F1 generation:
- The F1 offspring will all be heterozygous for both traits (YyRr).
F2 generation:
- When the F1 offspring are allowed to self-fertilize, the resulting F2 generation will have a phenotypic ratio of 9:3:3:1.
- This ratio is derived from the four possible combinations of alleles from the two traits: YR, Yr, yR, and yr.
- The expected ratios for each phenotype are:
- Yellow and round (YyRr or YYRR or YYRr or YyRR): 9/16 or 56.25%
- Yellow and wrinkled (Yyrr or YYrr): 3/16 or 18.75%
- Green and round (yyRr or yyRR): 3/16 or 18.75%
- Green and wrinkled (yyrr): 1/16 or 6.25%
Ratio of parental to recombinant phenotype:
- Parental phenotypes are those that match the phenotypes of the parents (YYrr and yyRR).
- Recombinant phenotypes are those that have new combinations of traits not seen in the parents (Yyrr and yyRr).
- In this cross, the ratio of parental to recombinant phenotypes is 10:6 or simplified to 5:3, which is option C in the given choices.
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A dihybrid cross is made between YYrr and yyRR. In F2 generation, the ...
In a Mendal dihybrid cross, in the F2 generation, 16 progeny are formed. In these progeny, 10 progeny show parental phenotypes (9 Yellow round + 1 green wrinkled) and 6 progeny show recombinant phenotypes (3 Yellow wrinkled + 3 green round).
That's why the ratio is 10:6
Hope it's help....
That's why the ratio is 10:6
Hope it's help....
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A dihybrid cross is made between YYrr and yyRR. In F2 generation, the ratio of parental to recombinant phenotype is:a)9 : 7b)6 : 10c)10 : 6d)7 : 9Correct answer is option 'C'. Can you explain this answer?
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