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Combustion of glucose takes place according to the reaction: C₆H₁₂O₆ → 6CO₂ + 6H₂O. If change in enthalpy in the reaction is -300 KJ, then heat evolved in the combustion of 1.5 g of glucose will be (Molecular weight of glucose = 180)
  • a)
    1.5 KJ
  • b)
    2.5 KJ
  • c)
    3.5 KJ
  • d)
    5.5 KJ
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Combustion of glucose takes place according to the reaction: CHO &rarr...
For 180 g glucose=> 300 kj energy is evolved.. then
for 1.5 g glucose => ?. i.e = 300×1.5/180 = 2.5 kj
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Community Answer
Combustion of glucose takes place according to the reaction: CHO &rarr...
For 180g of glucose 300KJ of energy is evolved then,for 1.5g of glucose how much energy is evolved. Cross multiply and check (300×1.5/180=2.5)
you will get 2.5KJ
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Combustion of glucose takes place according to the reaction: CHO → 6CO + 6HO. If change in enthalpy in the reaction is -300 KJ, then heat evolved in the combustion of 1.5 g of glucose will be (Molecular weight of glucose = 180)a)1.5 KJb)2.5 KJc)3.5 KJd)5.5 KJCorrect answer is option 'B'. Can you explain this answer?
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Combustion of glucose takes place according to the reaction: CHO → 6CO + 6HO. If change in enthalpy in the reaction is -300 KJ, then heat evolved in the combustion of 1.5 g of glucose will be (Molecular weight of glucose = 180)a)1.5 KJb)2.5 KJc)3.5 KJd)5.5 KJCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Combustion of glucose takes place according to the reaction: CHO → 6CO + 6HO. If change in enthalpy in the reaction is -300 KJ, then heat evolved in the combustion of 1.5 g of glucose will be (Molecular weight of glucose = 180)a)1.5 KJb)2.5 KJc)3.5 KJd)5.5 KJCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Combustion of glucose takes place according to the reaction: CHO → 6CO + 6HO. If change in enthalpy in the reaction is -300 KJ, then heat evolved in the combustion of 1.5 g of glucose will be (Molecular weight of glucose = 180)a)1.5 KJb)2.5 KJc)3.5 KJd)5.5 KJCorrect answer is option 'B'. Can you explain this answer?.
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