9.7×10^17 atoms of iron weighs as much as 1cc of H2 at S.T.P. What is ...
We know for gases at STP - 1mol of gas has a volume of 22.4L or 22,400cc (cm cube)For H2. 2.016g of H2 at STP = 22,400ccMass of 1 cc of H2 = 2.016 /22400 = 0.00009g We know is that 1 mol of anything contains 6.022*10^23 molecules or atoms for monoatomic elements. So, from the question: 9.7*10^17 atoms of Fe has mass = 0.00009g 6.022*10^23 atoms has mass = (6.022*10^23)/ (9.7*10^17) * 0.00009 = 55.87g Answer: 1 mol Fe has mass = 55.87g OR atomic mass of Fe = 55.87
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9.7×10^17 atoms of iron weighs as much as 1cc of H2 at S.T.P. What is ...
The atomic mass of iron can be calculated based on the given information. We are given that 9.7×10^17 atoms of iron weighs as much as 1cc of H2 at standard temperature and pressure (STP). To find the atomic mass of iron, we need to understand what "cc" represents in this context.
CC stands for cubic centimeter, which is a unit of volume. It is equivalent to the volume of a cube with sides of 1 centimeter. In this case, 1cc of H2 refers to 1 cubic centimeter of hydrogen gas.
To find the atomic mass of iron, we can follow the steps below:
Step 1: Determine the mass of 1cc of H2
- 1cc of H2 is given to be equivalent in weight to 9.7×10^17 atoms of iron.
- We know that the atomic mass of hydrogen (H) is approximately 1 gram per mole (g/mol).
- Therefore, the mass of 1cc of H2 can be calculated by multiplying the number of moles of hydrogen gas in 1cc by the molar mass of hydrogen.
- The molar mass of hydrogen is 2 grams per mole (g/mol) since hydrogen gas (H2) consists of two hydrogen atoms.
- Thus, the mass of 1cc of H2 is 2 grams.
Step 2: Determine the molar mass of iron
- We are given that 9.7×10^17 atoms of iron weigh the same as 1cc of H2, which is 2 grams.
- To find the molar mass of iron, we need to convert the given mass of iron to moles.
- Since the molar mass of iron is unknown, we can represent it as "x" grams per mole (g/mol).
- Using the given weight equivalence, we can set up the following equation:
9.7×10^17 atoms of iron / Avogadro's number = 2 grams / x g/mol
(Avogadro's number is approximately 6.022 × 10^23 atoms per mole)
- Solving for "x" gives us the molar mass of iron.
- By cross-multiplication, we get:
9.7×10^17 * x = 2 * Avogadro's number
x = (2 * Avogadro's number) / (9.7×10^17)
Step 3: Calculate the molar mass of iron
- Plugging in the value of Avogadro's number, we can calculate the molar mass of iron as:
x = (2 * 6.022 × 10^23) / (9.7×10^17)
x ≈ 3.110 grams per mole (g/mol)
Therefore, the atomic mass of iron is approximately 3.110 grams per mole (g/mol).
9.7×10^17 atoms of iron weighs as much as 1cc of H2 at S.T.P. What is ...
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