UPSC Question  >   If log2X + log4X = log0.25√6 and x > 0, then... Save
 If log2X + log4X = log0.25√6 and x > 0, then x is
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Answers

Ramcharan Lal
Aug 11, 2020
Related  If log2X + log4X = log0.25√6 and x > 0, then x is Related: Logarithms - Important Formulas, Quantitative Aptitude?
Log2x+log4x=log0.25√6
[log(a×b) =loga+logb]
log(2x×4x) =log0.25√6
from antilog-
2x×4x=0.25√6
8x=0.25√6
x=25√6÷800
x=√6÷32
x=0.0765

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This question for UPSC 2022 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about this question covers all topics & solutions for UPSC 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for  If log2X + log4X = log0.25√6 and x > 0, then x is Related: Logarithms - Important Formulas, Quantitative Aptitude?.
Log2x+log4x=log0.25√6[log(a×b) =loga+logb]log(2x×4x) =log0.25√6from antilog-2x×4x=0.25√68x=0.25√6x=25√6÷800x=√6÷32x=0.0765