If log2X + log4X = log0.25√6 and x > 0, then x is
?

UPSC Question

By Ironman A · Aug 10, 2020 ·UPSC
Ramcharan Lal answered Aug 11, 2020
Log2x+log4x=log0.25√6
[log(a×b) =loga+logb]
log(2x×4x) =log0.25√6
from antilog-
2x×4x=0.25√6
8x=0.25√6
x=25√6÷800
x=√6÷32
x=0.0765

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