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 If log2X + log4X = log0.25√6 and x > 0, then x is
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Ramcharan Lal
Aug 11, 2020
Related  If log2X + log4X = log0.25√6 and x > 0, then x is Related: Logarithms - Important Formulas, Quantitative Aptitude?
Log2x+log4x=log0.25√6
[log(a×b) =loga+logb]
log(2x×4x) =log0.25√6
from antilog-
2x×4x=0.25√6
8x=0.25√6
x=25√6÷800
x=√6÷32
x=0.0765

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Log2x+log4x=log0.25√6[log(a×b) =loga+logb]log(2x×4x) =log0.25√6from antilog-2x×4x=0.25√68x=0.25√6x=25√6÷800x=√6÷32x=0.0765