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The volume of 1.5 HCl required to completely react with 2.4g Mg is Mg 2HCl --- MgCl2 H2.?
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Calculating the volume of HCl required to react with Mg
- First, calculate the number of moles of Mg present:
Given mass of Mg = 2.4g
Molar mass of Mg = 24.3 g/mol
Number of moles of Mg = 2.4g / 24.3 g/mol = 0.0988 moles
- The balanced chemical equation for the reaction between Mg and HCl is:
Mg + 2HCl → MgCl2 + H2
- From the equation, we see that 1 mole of Mg reacts with 2 moles of HCl.
So, the number of moles of HCl required to react with Mg = 0.0988 moles * 2 = 0.1976 moles
- Now, we need to convert moles of HCl to volume using the molarity of the HCl solution. Let's assume the molarity of the HCl solution is 'x' mol/L.
- The volume of HCl required can be calculated using the formula:
Volume (L) = Number of moles / Molarity
Volume = 0.1976 moles / x mol/L
- Given that the molarity of the HCl solution is 1.5 mol/L:
Volume = 0.1976 moles / 1.5 mol/L = 0.1317 L or 131.7 mL
Therefore, 131.7 mL of 1.5 M HCl is required to completely react with 2.4g of Mg.
- First, calculate the number of moles of Mg present:
Given mass of Mg = 2.4g
Molar mass of Mg = 24.3 g/mol
Number of moles of Mg = 2.4g / 24.3 g/mol = 0.0988 moles
- The balanced chemical equation for the reaction between Mg and HCl is:
Mg + 2HCl → MgCl2 + H2
- From the equation, we see that 1 mole of Mg reacts with 2 moles of HCl.
So, the number of moles of HCl required to react with Mg = 0.0988 moles * 2 = 0.1976 moles
- Now, we need to convert moles of HCl to volume using the molarity of the HCl solution. Let's assume the molarity of the HCl solution is 'x' mol/L.
- The volume of HCl required can be calculated using the formula:
Volume (L) = Number of moles / Molarity
Volume = 0.1976 moles / x mol/L
- Given that the molarity of the HCl solution is 1.5 mol/L:
Volume = 0.1976 moles / 1.5 mol/L = 0.1317 L or 131.7 mL
Therefore, 131.7 mL of 1.5 M HCl is required to completely react with 2.4g of Mg.
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The volume of 1.5 HCl required to completely react with 2.4g Mg is Mg 2HCl --- MgCl2 H2.?
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The volume of 1.5 HCl required to completely react with 2.4g Mg is Mg 2HCl --- MgCl2 H2.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The volume of 1.5 HCl required to completely react with 2.4g Mg is Mg 2HCl --- MgCl2 H2.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The volume of 1.5 HCl required to completely react with 2.4g Mg is Mg 2HCl --- MgCl2 H2.?.
The volume of 1.5 HCl required to completely react with 2.4g Mg is Mg 2HCl --- MgCl2 H2.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The volume of 1.5 HCl required to completely react with 2.4g Mg is Mg 2HCl --- MgCl2 H2.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The volume of 1.5 HCl required to completely react with 2.4g Mg is Mg 2HCl --- MgCl2 H2.?.
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