A convex lens has a focal length f. It is cut into two parts along a line perpendicular to principal axis. The focal length of each part will be

- a)f/2
- b)f
- c)3/2 f
- d)2 f

Correct answer is option 'D'. Can you explain this answer?

Related Test: BITSAT Mock Test 5

Kurakula Suryateja
answered
4 weeks ago

Len's Maker's formula:-

f1â€‹=(Î¼âˆ’1)(R1â€‹1â€‹âˆ’R2â€‹1â€‹)

For equi-convex lens:-

Â f1â€‹=(Î¼âˆ’1)(R1â€‹âˆ’âˆ’R1â€‹)

âŸ¹f1â€‹=(Î¼âˆ’1)R2â€‹

For, the plano-convex lens formed:-

fâ€²1â€‹=(Î¼âˆ’1)(R1â€‹1â€‹âˆ’âˆž1â€‹)

fâ€²1â€‹=(Î¼âˆ’1)R1â€‹

âŸ¹fâ€²=2f

Answer-(D)

f1â€‹=(Î¼âˆ’1)(R1â€‹1â€‹âˆ’R2â€‹1â€‹)

For equi-convex lens:-

Â f1â€‹=(Î¼âˆ’1)(R1â€‹âˆ’âˆ’R1â€‹)

âŸ¹f1â€‹=(Î¼âˆ’1)R2â€‹

For, the plano-convex lens formed:-

fâ€²1â€‹=(Î¼âˆ’1)(R1â€‹1â€‹âˆ’âˆž1â€‹)

fâ€²1â€‹=(Î¼âˆ’1)R1â€‹

âŸ¹fâ€²=2f

Answer-(D)

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