Area of square ABCD is equal to the area of rectangle PQRS. If the length of rectangle PQRS is 21% more than its breadth, then what is the ratio of perimeter of ABCD to perimeter of PQRS?
- a)100:110
- b)210:220
- c)220: 221
- d)221: 220
- e)220: 210
Correct answer is option 'C'. Can you explain this answer?
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Answers
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Appoo Veena
May 17, 2022 |
Area of square=a^2; Area of rectangle=l*b
As per the question a^2=l*b
l=(121/100)b=121b/100
a^2=121b/100*b
a=11b/10
Perimeter of ABCD=4a=44b/10
Perimeter of PQRS=2(l + b)=2(b+121b/100)=442b/100
Ratio=
Perimeter of ABCD:
Perimeter of PQRS=44b/100:442b/100=220:221
Area of square=a^2; Area of rectangle=l*bAs per the question a^2=l*bl=(121/100)b=121b/100a^2=121b/100*ba=11b/10Perimeter of ABCD=4a=44b/10Perimeter of PQRS=2(l + b)=2(b+121b/100)=442b/100Ratio=Perimeter of ABCD:Perimeter of PQRS=44b/100:442b/100=220:221
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Area of square=a^2; Area of rectangle=l*bAs per the question a^2=l*bl=(121/100)b=121b/100a^2=121b/100*ba=11b/10Perimeter of ABCD=4a=44b/10Perimeter of PQRS=2(l + b)=2(b+121b/100)=442b/100Ratio=Perimeter of ABCD:Perimeter of PQRS=44b/100:442b/100=220:221
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