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The familiar brown ring test for nitrates depends on the ability of Fe2+ to reduce nitrates to nitric oxide, which reacts with Fe2+ to form a brown coloured complex [Fe(H2O)5NO+]SO4. What is the oxidation state of iron in the complex. (Only write the number 1, 2, 3, ......)
    Correct answer is '1433'. Can you explain this answer?
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    The familiar brown ring test for nitrates depends on the ability of Fe...
    Explanation:

    The oxidation state of iron in the complex is 3.
    - Iron (Fe) in the complex:
    In the complex [Fe(H2O)5NO+]SO4, iron (Fe) is present in the form of Fe(H2O)5NO+.
    - Formation of complex:
    When nitric oxide (NO) reacts with Fe2+, it forms a brown colored complex [Fe(H2O)5NO+]SO4.
    - Oxidation state of iron:
    To determine the oxidation state of iron in the complex, we need to consider the charges of the other elements present.
    - Charges of other elements:
    In the complex, the overall charge of the complex is +1.
    - Charge of NO:
    Nitric oxide (NO) has a charge of +1.
    - Charge of H2O:
    Water (H2O) has a neutral charge.
    - Charge of SO4:
    Sulfate (SO4) has a charge of -2.
    - Calculation:
    Considering the charges of NO, H2O, and SO4, the oxidation state of iron in the complex can be calculated as follows:
    x + 5(0) + 1 - 2 = +1
    x + 1 - 2 = +1
    x - 1 = +1
    x = 3
    - Conclusion:
    Therefore, the oxidation state of iron in the complex [Fe(H2O)5NO+]SO4 is +3.
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    Crystal field theory views the bonding in complexes as arising from electrostatic interaction and considers the effect of the ligand charges on the energies of the metal ion d-orbitals.In this theory, a ligand lone pair is modelled as a point negative charge that repels electrons in the d-orbitals of the central metal ion. The theory concentrated on the resulting splitting of the d-orbitals in two groups with different energies and used that splitting to rationalize and correlate the optical spectra, thermodynamic stability, and magnetic properties of complexes. This energy splitting between the two sets of dorbitals is called the crystal field splitting D.In general, the crystal field splitting energy D corresponds to wavelength of light in visible region of the spectrum, and colours of the complexes can therefore be attributed to electronic transition between the lower-and higher energy sets of d-orbitals.In general, the colour that the we see is complementry to the colour absorbed.Different metal ion have different values of D, which explains why their complexes with the same ligand have different colour.Similarly, the crystal field splitting also depends on the nature of ligands and as the ligand for the same metal varies from H2O to NH3 to ethylenediamine, D for complexes increases. Accordingly, the electronic transition shifts to higher energy (shorter wavelength) as the ligand varies from H2O to NH3 to en, thus accounting for the variation in colour.Crystal field theory accounts for the magnetic properties of complexes in terms of the relative values of and the spin pairing energy P. Small values favour high spin complexes, and large Dvalues favour low spin complexes.Which of the following statements is incorrect?

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    The familiar brown ring test for nitrates depends on the ability of Fe2+ to reduce nitrates to nitric oxide, which reacts with Fe2+ to form a brown coloured complex [Fe(H2O)5NO+]SO4. What is the oxidation state of iron in the complex. (Only write the number 1, 2, 3, ......)Correct answer is '1433'. Can you explain this answer?
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    The familiar brown ring test for nitrates depends on the ability of Fe2+ to reduce nitrates to nitric oxide, which reacts with Fe2+ to form a brown coloured complex [Fe(H2O)5NO+]SO4. What is the oxidation state of iron in the complex. (Only write the number 1, 2, 3, ......)Correct answer is '1433'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The familiar brown ring test for nitrates depends on the ability of Fe2+ to reduce nitrates to nitric oxide, which reacts with Fe2+ to form a brown coloured complex [Fe(H2O)5NO+]SO4. What is the oxidation state of iron in the complex. (Only write the number 1, 2, 3, ......)Correct answer is '1433'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The familiar brown ring test for nitrates depends on the ability of Fe2+ to reduce nitrates to nitric oxide, which reacts with Fe2+ to form a brown coloured complex [Fe(H2O)5NO+]SO4. What is the oxidation state of iron in the complex. (Only write the number 1, 2, 3, ......)Correct answer is '1433'. Can you explain this answer?.
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