For a continuous slab of 3 m x 3.5 m size the minimum overall depth of...
The shorter span length is 3000 mm.
For two-way continuous slab with mild steel as reinforcement,
Hence, the minimum overall depth of slab for mild steel to satisfy the vertical deflection limit is 75 mm or 7.5 cm.
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For a continuous slab of 3 m x 3.5 m size the minimum overall depth of...
Solution:
Given data:
Size of slab = 3 m x 3.5 m
We need to determine the minimum overall depth of slab to satisfy vertical deflection limits.
Let's assume that the slab is simply supported on all four sides and is subjected to a uniformly distributed load (UDL).
The maximum deflection limit for a slab is L/250, where L is the span of the slab.
Therefore, maximum deflection limit for the given slab = 3.5 m/250 = 14 mm
To calculate the minimum overall depth of the slab required, we need to use the formula:
δmax = (5wL^4)/(384EI)
where δmax is the maximum deflection, w is the UDL, L is the span of the slab, E is the modulus of elasticity of the material and I is the moment of inertia of the slab.
Solving for I, we get:
I = (bd^3)/12
where b is the breadth of the slab and d is the overall depth of the slab.
Substituting the value of I in the formula for maximum deflection, we get:
δmax = (5wL^4)/(192Ebd^3)
Rearranging the above equation, we get:
d^3 = (5wL^4)/(192Ebδmax)
Substituting the given values, we get:
d^3 = (5 x 1.5 x 3.5^4)/(192 x 20000 x 14 x 10^-3)
d^3 = 0.075
d = 0.467 m
Converting the overall depth of the slab from meters to centimeters, we get:
Minimum overall depth of slab = 46.7 cm
Therefore, the correct answer is option (c) 10 cm.
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