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The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer?.

Solutions for The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The H α line is the first member of the Balmer series of the hydrogen spectrum and it occurs due to the transition of the electron from the 3rd orbit to the 2ndorbit. If its wave length is λ , the wave length of the last member of the Balmer series will bea)(4/9) λb)(5/9) λc)(7/9) λd)(1/2) λCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.