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In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?
- a)Lead sulphate (insoluble)
- b)Lead acetate
- c)Ammonium nitrate
- d)Potassium sulphate
Correct answer is option 'B'. Can you explain this answer?
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In the double displacement reaction between aqueous potassium iodide a...
Pb(CH3COO)3 + 3KI → PbI3 + 3CH3COOK
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In the double displacement reaction between aqueous potassium iodide a...
**Answer:**
Lead nitrate (Pb(NO3)2) is a soluble salt that dissociates into lead ions (Pb2+) and nitrate ions (NO3-) when dissolved in water. It is commonly used in double displacement reactions as a source of lead ions.
In the given reaction, the potassium iodide (KI) reacts with lead nitrate (Pb(NO3)2) to form lead iodide (PbI2), which is a yellow precipitate. The balanced chemical equation for the reaction is:
2KI(aq) + Pb(NO3)2(aq) -> 2KNO3(aq) + PbI2(s)
If lead nitrate is not available, we need to find another compound that can provide lead ions in solution. Among the options given, lead acetate (Pb(C2H3O2)2) is the most suitable substitute.
**Explanation for choosing lead acetate:**
Lead acetate is a soluble salt that dissociates into lead ions (Pb2+) and acetate ions (C2H3O2-) when dissolved in water. It can provide the necessary lead ions for the reaction to occur.
The balanced chemical equation for the reaction between potassium iodide and lead acetate is:
2KI(aq) + Pb(C2H3O2)2(aq) -> 2K(C2H3O2)(aq) + PbI2(s)
In this reaction, the lead acetate reacts with potassium iodide to form lead iodide, which is the desired yellow precipitate, and potassium acetate, which remains dissolved in the solution.
**Explanation for other options:**
a) Lead sulphate (PbSO4) is an insoluble salt and will not dissociate into lead ions in solution. Therefore, it cannot be used as a substitute for lead nitrate.
c) Ammonium nitrate (NH4NO3) does not contain lead ions, so it cannot be used as a substitute for lead nitrate.
d) Potassium sulphate (K2SO4) does not contain lead ions, so it cannot be used as a substitute for lead nitrate.
Therefore, the correct option is b) Lead acetate, as it can provide the necessary lead ions for the reaction to occur and form the yellow precipitate of lead iodide.
Lead nitrate (Pb(NO3)2) is a soluble salt that dissociates into lead ions (Pb2+) and nitrate ions (NO3-) when dissolved in water. It is commonly used in double displacement reactions as a source of lead ions.
In the given reaction, the potassium iodide (KI) reacts with lead nitrate (Pb(NO3)2) to form lead iodide (PbI2), which is a yellow precipitate. The balanced chemical equation for the reaction is:
2KI(aq) + Pb(NO3)2(aq) -> 2KNO3(aq) + PbI2(s)
If lead nitrate is not available, we need to find another compound that can provide lead ions in solution. Among the options given, lead acetate (Pb(C2H3O2)2) is the most suitable substitute.
**Explanation for choosing lead acetate:**
Lead acetate is a soluble salt that dissociates into lead ions (Pb2+) and acetate ions (C2H3O2-) when dissolved in water. It can provide the necessary lead ions for the reaction to occur.
The balanced chemical equation for the reaction between potassium iodide and lead acetate is:
2KI(aq) + Pb(C2H3O2)2(aq) -> 2K(C2H3O2)(aq) + PbI2(s)
In this reaction, the lead acetate reacts with potassium iodide to form lead iodide, which is the desired yellow precipitate, and potassium acetate, which remains dissolved in the solution.
**Explanation for other options:**
a) Lead sulphate (PbSO4) is an insoluble salt and will not dissociate into lead ions in solution. Therefore, it cannot be used as a substitute for lead nitrate.
c) Ammonium nitrate (NH4NO3) does not contain lead ions, so it cannot be used as a substitute for lead nitrate.
d) Potassium sulphate (K2SO4) does not contain lead ions, so it cannot be used as a substitute for lead nitrate.
Therefore, the correct option is b) Lead acetate, as it can provide the necessary lead ions for the reaction to occur and form the yellow precipitate of lead iodide.
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In the double displacement reaction between aqueous potassium iodide a...
In this rxn potassium iodide (KI) and lead nitrite[Pb(No3)2] dissociate in their respective ions and lead combine to iodide ion and form lead iodide (PbI2) as precipitate so for that we need pb2+ ion which can be taken either form option A or option B but it is given that lead sulphate is insoluble so it will not form pb+2 ion so we have only one option which give us Pb+2 ion and that is option B
so ,option B is correct
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In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?a)Lead sulphate (insoluble)b)Lead acetatec)Ammonium nitrated)Potassium sulphateCorrect answer is option 'B'. Can you explain this answer?
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In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?a)Lead sulphate (insoluble)b)Lead acetatec)Ammonium nitrated)Potassium sulphateCorrect answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?a)Lead sulphate (insoluble)b)Lead acetatec)Ammonium nitrated)Potassium sulphateCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?a)Lead sulphate (insoluble)b)Lead acetatec)Ammonium nitrated)Potassium sulphateCorrect answer is option 'B'. Can you explain this answer?.
In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?a)Lead sulphate (insoluble)b)Lead acetatec)Ammonium nitrated)Potassium sulphateCorrect answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?a)Lead sulphate (insoluble)b)Lead acetatec)Ammonium nitrated)Potassium sulphateCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?a)Lead sulphate (insoluble)b)Lead acetatec)Ammonium nitrated)Potassium sulphateCorrect answer is option 'B'. Can you explain this answer?.
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