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The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 70 paise per cm2 is
- a)Rs 17
- b)Rs 16.80
- c)Rs 7
- d)Rs 16
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of ...
Edge of triangle are = 6cm, 8 cm and 10cm
S = a + b + C/2
S = 6+8+10/2
S = 24/2
S=12
area is = √s (S-a)(S-b) (S-C)
area is =√12 (12-6) (12-8) (12-10)
area is =√12x6x4x2
area is = √2x6x6X2X2X2
area is = 6x2x2 cm cm²
Area is = 24cm²
We convert Paise into Rupee
1 paise = 1/100 rupee
70 Paise = 70/100 rupee
70 paise = 0.7 rupee
The cost of Painting 24cm²=24x 0.7cm²
The cost of Painting = 16.80 cm²(Ans.)
S = a + b + C/2
S = 6+8+10/2
S = 24/2
S=12
area is = √s (S-a)(S-b) (S-C)
area is =√12 (12-6) (12-8) (12-10)
area is =√12x6x4x2
area is = √2x6x6X2X2X2
area is = 6x2x2 cm cm²
Area is = 24cm²
We convert Paise into Rupee
1 paise = 1/100 rupee
70 Paise = 70/100 rupee
70 paise = 0.7 rupee
The cost of Painting 24cm²=24x 0.7cm²
The cost of Painting = 16.80 cm²(Ans.)
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The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of ...
To calculate the cost of painting the triangular board, we need to find the area of the board first and then multiply it by the cost per square centimeter.
Let's use Heron's formula to find the area of the triangle:
Heron's formula:
Area = √(s(s-a)(s-b)(s-c))
where s is the semi-perimeter of the triangle, and a, b, and c are the lengths of the sides of the triangle.
In this case, the lengths of the sides are given as 6 cm, 8 cm, and 10 cm. Let's calculate the semi-perimeter first:
s = (6 + 8 + 10)/2
= 24/2
= 12 cm
Now, let's substitute the values into Heron's formula:
Area = √(12(12-6)(12-8)(12-10))
= √(12 * 6 * 4 * 2)
= √(576)
= 24 cm²
So, the area of the board is 24 cm².
Now, let's calculate the cost of painting the board. The rate is given as 70 paise per cm².
To convert paise into rupees, we divide the amount by 100. So, 70 paise = 70/100 = 0.7 rupees.
The cost of painting the board is the area multiplied by the rate:
Cost = Area * Rate
= 24 cm² * 0.7 rupees/cm²
= 16.8 rupees
Therefore, the cost of painting the triangular board is Rs 16.80, which is option B.
Let's use Heron's formula to find the area of the triangle:
Heron's formula:
Area = √(s(s-a)(s-b)(s-c))
where s is the semi-perimeter of the triangle, and a, b, and c are the lengths of the sides of the triangle.
In this case, the lengths of the sides are given as 6 cm, 8 cm, and 10 cm. Let's calculate the semi-perimeter first:
s = (6 + 8 + 10)/2
= 24/2
= 12 cm
Now, let's substitute the values into Heron's formula:
Area = √(12(12-6)(12-8)(12-10))
= √(12 * 6 * 4 * 2)
= √(576)
= 24 cm²
So, the area of the board is 24 cm².
Now, let's calculate the cost of painting the board. The rate is given as 70 paise per cm².
To convert paise into rupees, we divide the amount by 100. So, 70 paise = 70/100 = 0.7 rupees.
The cost of painting the board is the area multiplied by the rate:
Cost = Area * Rate
= 24 cm² * 0.7 rupees/cm²
= 16.8 rupees
Therefore, the cost of painting the triangular board is Rs 16.80, which is option B.
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The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 70 paise percm2 isa)Rs 17b)Rs 16.80c)Rs 7d)Rs 16Correct answer is option 'B'. Can you explain this answer? for Class 9 2025 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 70 paise percm2 isa)Rs 17b)Rs 16.80c)Rs 7d)Rs 16Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 9 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 70 paise percm2 isa)Rs 17b)Rs 16.80c)Rs 7d)Rs 16Correct answer is option 'B'. Can you explain this answer?.
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