If a×cos x + b × cos x = c, then the value of (a × sin x – b²cos x)² is
- a)a² + b² + c²
- b)a² - b² - c²
- c)a² - b² + c²
- d)a² + b² - c²
Correct answer is option 'D'. Can you explain this answer?
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Answers
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Mohit Rajpoot
May 07, 2021 |
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(a×cos x + b × sin x)² + (a × sin x – b × cos x)² = a² + b²
⇒ c² + (a × sin x – b × cos x)² = a² + b²
⇒ (a × sin x – b × cos x)² = a² + b² – c²
⇒ c² + (a × sin x – b × cos x)² = a² + b²
⇒ (a × sin x – b × cos x)² = a² + b² – c²
(a×cos x + b × sin x)² + (a × sin x – b × cos x)² = a² + b²⇒ c² + (a × sin x – b × cos x)² = a² + b²⇒ (a × sin x – b × cos x)² = a² + b² – c²
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(a×cos x + b × sin x)² + (a × sin x – b × cos x)² = a² + b²⇒ c² + (a × sin x – b × cos x)² = a² + b²⇒ (a × sin x – b × cos x)² = a² + b² – c²
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