6. A list contains 20 consecutive odd integers. The average of these i...
To find the largest odd integer in the list, we need to determine the first odd integer in the list and then increment it consecutively until we reach the largest odd integer.
Let's assume the first odd integer in the list is 'x'. Since the list contains consecutive odd integers, the next odd integer would be 'x + 2', the one after that would be 'x + 4', and so on.
We can find the sum of the list by using the average and the number of terms:
Average = Sum of terms / Number of terms
In this case, the average is given as 24 and the number of terms is 20. So, we can write the equation as:
24 = Sum of terms / 20
To find the sum of the terms, we can multiply the average by the number of terms:
Sum of terms = 24 * 20 = 480
Now, we can find the first odd integer in the list:
x + (x + 2) + (x + 4) + ... + (x + 38) = 480
To simplify the equation, we can group the terms:
20x + (2 + 4 + 6 + ... + 38) = 480
20x + 2(1 + 2 + 3 + ... + 19) = 480
20x + 2(19(19 + 1)/2) = 480
20x + 2(19 * 20/2) = 480
20x + 2(190) = 480
20x + 380 = 480
20x = 480 - 380
20x = 100
x = 100/20
x = 5
So, the first odd integer in the list is 5. Now, we need to find the largest odd integer in the list. Since the list contains consecutive odd integers, the largest odd integer would be the last term, which is 'x + 38' in this case.
Therefore, the largest odd integer in the list is 5 + 38 = 43.
Hence, the correct answer is option B) 43.
6. A list contains 20 consecutive odd integers. The average of these i...
B)43
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