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A Father Has 7 Pennys With Him And 1 Water Melon Is For 1p, 2chickoos For 1p, 3 Grapes Foe 1p. He Has Three Sons. How Can He Share The Fruits Equally?
  • a)
    1 Watermelon, 4 chickoos, 1 grape
  • b)
    1 Watermelon, 3 chickoos, 2 grape
  • c)
    1 Watermelon, 2 chickoos, 3 grape
  • d)
    1 Watermelon, 2 chickoos, 1 grape
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A Father Has 7 Pennys With Him And 1 Water Melon Is For 1p, 2chickoos ...
I am trying to give a solution based on my interpretation.
Suppose,
let the number of water melon be W then cost of 1 water melon is 1p.
let the number of chickoos be C then cost of 1 chichoo is 0.5p ( 1p= 2 chickoos)
let the number of grapes be G then cost of 1 grape is 0.33p ( 1p= 3 grapes)

let the equation of cost be as follows

1W+2C+3G --- for one person. 
Assumption looking at options - each son, atleast 1 water melon. so 3 sons - 1 watermelon each -- 1 X3=3p
total amount - cost of 3 watermelons = 7p-3p=4p. (equation for 3 people combined)

left is 2C+3G = 4 (total amount)
 
since C is the cost of chikoo- 1 rupee has 2 chikoo. cannot be divided among 3. We at least need 6 chikoos, so that we can distribute equally among 3 .there by 1 gets 2 chikoos and total cost of 6 chickoos will be 3p.
Total amount - cost of 6 chickoos = 4-3 =1(total amount)

left is 3G=1 (total amount)
since we have 1p left and we get 3 grapes for 1p, each of them can take 1 grape equally.

Hence option D.

Incase the logic feels difficult, use the options elimination method
write and equation for each option. Example taking option 1 :
1W - 1 p
4 chickoo = 2 p
1 grape =0.33p
total cost for 1 person = 3.33p
total cost for 3 people = 3.33p*3 = 9.99p~ 10P . More than 7 P no an option.

simlarly option 3 :
1W= 1 p
2C= 1p
3G = 1 p 
total cost  for 1 person =3p
total cost for 3 person =9p more than 7p

Simlarly option 4
1W=1p
2C=1p
1G=0.33p
total cost for 1 person =2.33p
total cost for 3 people is 2.33*3 =6.99p ~ 7p satisfies the answer

Hope this helps!







Free Test
Community Answer
A Father Has 7 Pennys With Him And 1 Water Melon Is For 1p, 2chickoos ...
Solution:

The father has 7 pennies with him and he needs to share the fruits equally among his three sons. Let's calculate the cost of each fruit.

- Watermelon: 1 watermelon is for 1 penny, so each watermelon costs 1/3 penny.
- Chickoo: 2 chickoos are for 1 penny, so each chickoo costs 1/2 penny.
- Grape: 3 grapes are for 1 penny, so each grape costs 1/3 penny.

Now we need to distribute the fruits in such a way that each son gets an equal share. Let's consider the options given:

a) 1 Watermelon, 4 Chickoos, 1 Grape

- Cost of Watermelon: 1/3 penny
- Cost of Chickoos: 4/2 = 2 pennies
- Cost of Grape: 1/3 penny
- Total cost: 7/3 pennies

This option is not feasible as the total cost is not divisible by 3.

b) 1 Watermelon, 3 Chickoos, 2 Grapes

- Cost of Watermelon: 1/3 penny
- Cost of Chickoos: 3/2 = 1.5 pennies
- Cost of Grapes: 2/3 penny
- Total cost: 7/3 pennies

This option is also not feasible as the total cost is not divisible by 3.

c) 1 Watermelon, 2 Chickoos, 3 Grapes

- Cost of Watermelon: 1/3 penny
- Cost of Chickoos: 2/2 = 1 penny
- Cost of Grapes: 3/3 = 1 penny
- Total cost: 7/3 pennies

This option is feasible as the total cost is divisible by 3.

d) 1 Watermelon, 2 Chickoos, 1 Grape

- Cost of Watermelon: 1/3 penny
- Cost of Chickoos: 2/2 = 1 penny
- Cost of Grape: 1/3 penny
- Total cost: 4/3 pennies

This option is also feasible as the total cost is divisible by 3.

Hence, options (c) and (d) are feasible. But option (d) has fewer fruits, so it is the best option. Therefore, the father can share the fruits equally among his three sons by giving them 1 watermelon, 2 chickoos, and 1 grape each.
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Question Description
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