Let the 4 digit no. be xyzw.According to given conditions we have x + y = z + w, x + w = z, y + w = 2x + 2z.With help of these equations, we deduce that y = 2w, z = 5x.Now the minimum value x can take is 1 so z = 5 and the no. is 1854, which satisfies all the conditions.Hence Option A is correctFor Complete syllabus ofQuant for CATclick on the link given below:Quantitative Aptitude (Quant)https://edurev.in/courses/3074_quantitative-aptitude--maths--prep-tests--videos-