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A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.
Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.
Q. The magnifying power of a compound microscope increases with
- a)the focal length of objective lens is increased and that of eye lens is decreased.
- b)the focal length of eye lens is increased and that of objective lens is decreased.
- c)focal length of both objects and eye-piece are increased.
- d)focal length of both objects and eye-piece are decreased.
Correct answer is option 'D'. Can you explain this answer?
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A compound microscope is an optical instrument used for observing hig...
We know the formula for magnification of compound microscope,
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Here, l is the length of the tube, fo is the focal length of the objective lens, D is the distance of distinct vision and fe is the focal length of the eyepiece lens.
We can write the proportionality of the terms in the above formula as,
From the above formula, we can conclude that the magnifying power of the compound microscope increases when the focal lengths of both objective and eyepiece lenses decrease.
So, the correct answer is option (D).
Most Upvoted Answer
A compound microscope is an optical instrument used for observing hig...
We know the formula for magnification of compound microscope,
Here, l is the length of the tube, fo is the focal length of the objective lens, D is the distance of distinct vision and fe is the focal length of the eyepiece lens.
We can write the proportionality of the terms in the above formula as,
From the above formula, we can conclude that the magnifying power of the compound microscope increases when the focal lengths of both objective and eyepiece lenses decrease.
So, the correct answer is option (D).
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A compound microscope is an optical instrument used for observing hig...
Understanding Magnifying Power
The magnifying power of a compound microscope is crucial for observing tiny objects. It is influenced by the focal lengths of the objective lens and eyepiece.
Factors Affecting Magnifying Power
1. Objective Lens Magnification (mo):
- A shorter focal length of the objective lens produces a larger magnification.
- This is because a shorter focal length allows for a greater bending of light rays, which leads to a larger image.
2. Eyepiece Magnification (me):
- Similarly, a shorter focal length of the eyepiece increases its magnification.
- A shorter focal length eyepiece allows the viewer to see a larger angular size of the image.
Effect of Focal Length Changes
- Option A: Increasing the focal length of the objective lens while decreasing the eyepiece's focal length will not effectively increase magnification since the objective's contribution is reduced.
- Option B: Increasing the eyepiece's focal length while decreasing the objective's focal length decreases the overall magnifying power, as the objective needs to provide a higher magnification.
- Option C: Increasing the focal lengths of both lenses leads to a decrease in magnifying power due to reduced bending of light rays and decreased image size.
- Option D (Correct Answer): Decreasing the focal lengths of both the objective lens and eyepiece increases the magnifying power. This is because:
- A smaller focal length for the objective increases mo.
- A smaller focal length for the eyepiece increases me, leading to a higher product (m = me x mo).
Conclusion
Thus, the magnifying power of a compound microscope increases when both the focal lengths of the objective lens and eyepiece are decreased, making option D the correct choice.
The magnifying power of a compound microscope is crucial for observing tiny objects. It is influenced by the focal lengths of the objective lens and eyepiece.
Factors Affecting Magnifying Power
1. Objective Lens Magnification (mo):
- A shorter focal length of the objective lens produces a larger magnification.
- This is because a shorter focal length allows for a greater bending of light rays, which leads to a larger image.
2. Eyepiece Magnification (me):
- Similarly, a shorter focal length of the eyepiece increases its magnification.
- A shorter focal length eyepiece allows the viewer to see a larger angular size of the image.
Effect of Focal Length Changes
- Option A: Increasing the focal length of the objective lens while decreasing the eyepiece's focal length will not effectively increase magnification since the objective's contribution is reduced.
- Option B: Increasing the eyepiece's focal length while decreasing the objective's focal length decreases the overall magnifying power, as the objective needs to provide a higher magnification.
- Option C: Increasing the focal lengths of both lenses leads to a decrease in magnifying power due to reduced bending of light rays and decreased image size.
- Option D (Correct Answer): Decreasing the focal lengths of both the objective lens and eyepiece increases the magnifying power. This is because:
- A smaller focal length for the objective increases mo.
- A smaller focal length for the eyepiece increases me, leading to a higher product (m = me x mo).
Conclusion
Thus, the magnifying power of a compound microscope increases when both the focal lengths of the objective lens and eyepiece are decreased, making option D the correct choice.
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A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer?
Question Description
A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer?.
A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer?.
Solutions for A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The magnifying power of a compound microscope increases witha)the focal length of objective lens is increased and that of eye lens is decreased.b)the focal length of eye lens is increased and that of objective lens is decreased.c)focal length of both objects and eye-piece are increased.d)focal length of both objects and eye-piece are decreased.Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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