1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?
  • a)
    O2 is a limiting reagent and Mg is in excess by 0.25 g
  • b)
    Mg is a limiting reagent and is in excess by 0.5 g
  • c)
    O2 is a limiting reagent and is in excess by 0.25 g
  • d)
    O2 is a limiting reagent and Mg is in excess by 0.75 g
Correct answer is option 'A'. Can you explain this answer?

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Answers

Diwakar Singh
Jan 18, 2022

48 g of Mg requires 32 g of O2
1 g of Mg requires 32/48 = 0.66 g of O2
Oxygen available = 0.5 g
Hence, O2 is limiting reagent.
32 g of O2 reacts with 48 g of Mg
0.5 g of O2 will react with 48/32 x 0.5 = 0.75 g of Mg
Excess of Mg = (1.0 - 0.75) = 0.25 g

48 g of Mg requires 32 g of O21 g of Mg requires 32/48 = 0.66 g of O2Oxygen available = 0.5 gHence, O2 is limiting reagent.32 g of O2 reacts with 48 g of Mg0.5 g of O2 will react with 48/32 x 0.5 = 0.75 g of MgExcess of Mg = (1.0 - 0.75) = 0.25 g
48 g of Mg requires 32 g of O21 g of Mg requires 32/48 = 0.66 g of O2Oxygen available = 0.5 gHence, O2 is limiting reagent.32 g of O2 reacts with 48 g of Mg0.5 g of O2 will react with 48/32 x 0.5 = 0.75 g of MgExcess of Mg = (1.0 - 0.75) = 0.25 g