What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produce 10 g of BaSO4?
  • a)
    8.58 mL
  • b)
    7.2 mL
  • c)
    10 mL
  • d)
    12 mL
Correct answer is option 'A'. Can you explain this answer?

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Answers

Bs Academy
Jan 19, 2022
Na2SO4 + BaCI2 → BaSO4 + 2NaCl
No. of moles of BaSO4 = w/M = 10/233 = 0.0429
∴ No. of moles of Na2SO4 needed = M x V/1000
Or 0.0429 = 5 x V/1000
V = 8.58 mL

Na2SO4 + BaCI2 → BaSO4 + 2NaClNo. of moles of BaSO4 = w/M = 10/233 = 0.0429∴No. of moles of Na2SO4 needed = M x V/1000Or 0.0429 = 5 x V/1000V =8.58 mL
Na2SO4 + BaCI2 → BaSO4 + 2NaClNo. of moles of BaSO4 = w/M = 10/233 = 0.0429∴No. of moles of Na2SO4 needed = M x V/1000Or 0.0429 = 5 x V/1000V =8.58 mL