In case of a Van de Graaff generator, the breakdown field of air is
- a)2 × 108 V m−1
- b)3 × 106V m−1
- c)2 × 10−8V m−1
- d)3 × 104V m−1
Correct answer is option 'B'. Can you explain this answer?
Related Test
Although air is normally an insulator but at a sufficient high voltage, it ionises and become partially conducting.The electric field at which it occurs is called breakdown field of air and is nearly equal to 3 × 106V/m-1
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Although air is normally an insulator but at a sufficient high voltage, it ionises and become partially conducting.The electric field at which it occurs is called breakdown field of air and is nearly equal to 3 × 106V/m-1
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