Equivalent resistance (in ohm) of the given network is
  • a)
    28
  • b)
    18
  • c)
    26
  • d)
    25
Correct answer is option 'B'. Can you explain this answer?

Related Test

Answers

EduRev NEET
Jan 21, 2022
Between points A and B all resistances are combined in series
∴ Req = 3Ω + 4Ω + 5Ω + 6Ω
= 18Ω
Between points A and B all resistances are combined in series
∴ Req = 3Ω + 4Ω + 5Ω + 6Ω
= 18Ω

Between points A and B all resistances are combined in series∴ Req= 3Ω + 4Ω + 5Ω + 6Ω= 18ΩBetween points A and B all resistances are combined in series∴ Req= 3Ω + 4Ω + 5Ω + 6Ω= 18Ω
Between points A and B all resistances are combined in series∴ Req= 3Ω + 4Ω + 5Ω + 6Ω= 18ΩBetween points A and B all resistances are combined in series∴ Req= 3Ω + 4Ω + 5Ω + 6Ω= 18Ω