Equivalent resistance (in ohm) of the given network is
- a)28
- b)18
- c)26
- d)25
Correct answer is option 'B'. Can you explain this answer?
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EduRev NEET
Jan 21, 2022 |
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Between points A and B all resistances are combined in series
∴ Req = 3Ω + 4Ω + 5Ω + 6Ω
= 18Ω
Between points A and B all resistances are combined in series
∴ Req = 3Ω + 4Ω + 5Ω + 6Ω
= 18Ω
∴ Req = 3Ω + 4Ω + 5Ω + 6Ω
= 18Ω
Between points A and B all resistances are combined in series
∴ Req = 3Ω + 4Ω + 5Ω + 6Ω
= 18Ω
Between points A and B all resistances are combined in series∴ Req= 3Ω + 4Ω + 5Ω + 6Ω= 18ΩBetween points A and B all resistances are combined in series∴ Req= 3Ω + 4Ω + 5Ω + 6Ω= 18Ω
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Between points A and B all resistances are combined in series∴ Req= 3Ω + 4Ω + 5Ω + 6Ω= 18ΩBetween points A and B all resistances are combined in series∴ Req= 3Ω + 4Ω + 5Ω + 6Ω= 18Ω
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