n resistors each of resistance R first combine to give maximum effective resistgance and then combine to give minimum. The ratio of the maximum resistance is
a)
n
b)
n2
c)
n2 − 1
d)
n3
Correct answer is option 'B'. Can you explain this answer?
To get maximum equivalent resistance all resistances must be connected in series ∴ (Req)max = R + R + R...ntimes = nR To get minimum equivalent resistance all resistances myst be connected in parallel. ∴
To get maximum equivalent resistance all resistances must be connected in series∴ (Req)max= R + R + R...ntimes = nRTo get minimum equivalent resistance all resistances myst be connected in parallel.∴
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To get maximum equivalent resistance all resistances must be connected in series∴ (Req)max= R + R + R...ntimes = nRTo get minimum equivalent resistance all resistances myst be connected in parallel.∴