Three resistances 2Ω, 4Ω, 5Ω are combined in series and this combination is connected to a battery of 12 V emf and negligible internal resistance. The potential drop across these resistances are
• a)
(5,45,4.36,2.18)V
• b)
(2,18,5.45,4.36)V
• c)
(4.36,2.18,5.45)V
• d)
(2.18,4.36,5.45)V

### Related Test

Let current in the circuit is I. Then total resistance in the circuit.
R = R1 + R2 + R3 = 2 + 4 + 5 = 11Ω
∴
The potential drop across 2Ω resistance

The potential drop across 4Ω resistance

The potential drop across 5Ω resistance

Hence(V1, V2, V3) = (2.18, 4.36, 5.45)V

Let current in the circuit is I. Then total resistance in the circuit.R = R1 + R2 + R3 = 2 + 4 + 5 = 11Ω∴The potential drop across 2Ω resistanceThe potential drop across 4Ω resistanceThe potential drop across 5Ω resistanceHence(V1, V2, V3) = (2.18, 4.36, 5.45)V

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