A 16 pF capacitor is connected to 70 V supply. The amount of electric energy stored in the capacitor is
- a)4.5 × 10−12J
- b)5.1 × 10−8J
- c)2.5 × 10−12J
- d)3.92 × 10−8J
Correct answer is option 'D'. Can you explain this answer?
Related Test
Here C = 16pF = 16 × 10−12FV = 80V
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Here C = 16pF = 16 × 10−12FV = 80V
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