A parallel plate condenser with a dielectric of dielectric constant K between the plates has a capacity C and is charged to a potential V volt. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is
  • a)
    zero
  • b)
  • c)
  • d)
    (K - 1)CV2
Correct answer is option 'A'. Can you explain this answer?

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Answers

Lead Academy
Feb 12, 2022
The potential energy of a charged capacitor before removing the dielectric slat is U = Q2/2C.
The potential energy of the capacitor when the dielectric slat is first removed and the reinserted in the gap between the plates is U = Q2/2C
There is no change in potential energy, therefore work done is zero.

The potential energy of a charged capacitor before removing the dielectric slat is U = Q2/2C.The potential energy of the capacitor when the dielectric slat is first removed and the reinserted in the gap between the plates is U = Q2/2CThere is no change in potential energy, therefore work done is zero.
The potential energy of a charged capacitor before removing the dielectric slat is U = Q2/2C.The potential energy of the capacitor when the dielectric slat is first removed and the reinserted in the gap between the plates is U = Q2/2CThere is no change in potential energy, therefore work done is zero.