Minimum number of capacitors each of 8μF and 250V used to make a composite capacitor of 16μF and 1000V are

- a)8
- b)32
- c)16
- d)24

Correct answer is option 'B'. Can you explain this answer?

Shiksha Academy
Feb 11, 2022 |

Minimum number of capacitors in each row = 1000/250 = 4

Therefore, 4 capacitors connected in series.

If there are m such rows, that total capacity

= m × 2 = 16 ∴ m = 16/28

∴ minimum number of capacitors = 4 × 8 = 32

Therefore, 4 capacitors connected in series.

If there are m such rows, that total capacity

= m × 2 = 16 ∴ m = 16/28

∴ minimum number of capacitors = 4 × 8 = 32

Minimum number of capacitors in each row = 1000/250 = 4Therefore, 4 capacitors connected in series.If there are m such rows, that total capacity= m × 2 = 16 ∴ m = 16/28∴ minimum number of capacitors = 4 × 8 = 32

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