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A solid AB has a rock salt structure. If radius of cation A+ is 120 pm, what is the minimum value of radius of B anion?
  • a)
    120 pm
  • b)
    240 pm
  • c)
    290 pm
  • d)
    360 pm
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A solid AB has a rock salt structure. If radius of cation A+is 120 pm,...
Limited Ratio 

⟹rB− = 290 pm
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A solid AB has a rock salt structure. If radius of cation A+is 120 pm,...
In a rock salt structure, the cations and anions are arranged in a face-centered cubic lattice. Each cation is surrounded by 6 anions and vice versa.

The radius of cation A is given as 120 pm. This means that the distance between the centers of adjacent cations in the lattice is 2 × 120 pm = 240 pm.

Since each cation is surrounded by 6 anions, the distance between the center of the cation and the center of an adjacent anion is equal to the radius of the anion plus the radius of the cation. Let the radius of anion B be rB.

Therefore, the distance between the centers of adjacent cation and anion is:

240 pm = rB + 120 pm

Solving for rB, we get:

rB = 240 pm - 120 pm = 120 pm

So, the minimum value of the radius of anion B in a rock salt structure with cation A having a radius of 120 pm is 120 pm.
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A solid AB has a rock salt structure. If radius of cation A+is 120 pm, what is the minimum value of radius of B−anion?a)120 pmb)240 pmc)290 pmd)360 pmCorrect answer is option 'C'. Can you explain this answer?
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