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If 110 g of copper sulphate is present in 550 g of solution, what will be the concentration of
solution?
  • a)
    11%
  • b)
    20%
  • c)
    55%
  • d)
    22%
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If 110 g of copper sulphate is present in 550 g of solution, what wil...
Solution:

Given:
Mass of copper sulphate = 110 g
Mass of solution = 550 g

To find:
Concentration of solution

Concentration is defined as the amount of solute (in this case, copper sulphate) present in a given amount of solution.

Concentration of solution = (mass of solute / mass of solution) * 100

Substituting the given values into the formula:

Concentration = (110 g / 550 g) * 100

Simplifying the expression:

Concentration = (1/5) * 100 = 20%

Therefore, the concentration of the solution is 20%.

Explanation:

To calculate the concentration of a solution, we need to determine the ratio of the mass of the solute to the mass of the solution and express it as a percentage.

In this case, the mass of copper sulphate is given as 110 g and the mass of the solution is given as 550 g. To find the concentration, we divide the mass of the solute by the mass of the solution and multiply by 100 to express it as a percentage.

Substituting the given values into the formula, we get (110 g / 550 g) * 100 = (1/5) * 100 = 20%.

Therefore, the concentration of the solution is 20%.

This means that for every 100 g of the solution, there are 20 g of copper sulphate present.
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Community Answer
If 110 g of copper sulphate is present in 550 g of solution, what wil...
Mass by mass percentage of a solution = [(Mass of solute) / (Mass of solution)] X 100
Here, mass of solute ( cuSo4) = 110g
Mass of solution = 550 g
Therefore mass by mass percentage of solution = (110 X 100) / 550= 20%
Hence, the concentration of the solution is 20%.
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