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O is the center of the circle, with AC = 30 cm and DA = 10√5 cm, then the measure of DC is 
  • a)
    10√5 cm
  • b)
    20 cm
  • c)
    20√5 cm
  • d)
    25 cm 
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
O is the center of the circle, with AC = 30 cm and DA = 10√5 cm,...
In ∆ACD, 
∠ADC = 90° [∵∠ACD is angle in semicircle]
∴  AC2 = DA2 + DC2
⇒ (30)2 = (10√5 )2 + DC2
⇒ DC2 = 900 – 500 
⇒ DC = √400 = 20 cm. 
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