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Given: f(x) = Let, y2 = 9 - x2⇒ x2 = 9 - y2x = ...(1)We know that for any function f(x)= ,y ≥ 0…. (A)From equation (1).9 − y2 ≥ 0y2 − 9 ≤ 0⇒ (y + 3)(y − 3) ≤ 0⇒ −3 ≤ y ≤ 3But from equation (A) y must be positive, then, y = [0, 3].Range = the value of y = [0, 3]Hence, the correct answer is [0, 3].
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