CAT Question > How many sets of three distinct factors of t...
Related Test
How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?
- a)236
- b)360
- c)104
- d)380
Correct answer is option 'A'. Can you explain this answer?
Answers
N = 26 × 34 × 52
Case: [A]
when none of the elements is 1 ⇒ the three factors must be some powers of 2, 3, 5 respectively.
⇒ total number of such sets = 6 × 4 × 2 = 48
Case: [B]
when one of the elements is 1
⇒ the other two factors could be of the form (2a), (3b) − number of sets = 6 × 4 = 24
(26), (52) − number of sets = 6 × 2 = 12
(34),(52) − number of sets = 4 × 2 = 8
(26 × 34 × 52) − number of sets = 6 × 4 × 2 = 48
(26 × 52 × 34) − number of sets = 6 × 2 × 4 = 48
(34 × 52 × 26) − number of sets = 4 × 2 × 6 = 48
∴ total number of such sets = 188
combining both the cases, total sets possible
= 188 + 48 = 236
 | View courses related to this question | Explore CAT courses |
Explore CAT courses View courses related to this question |  |
| 1 Crore+ students have signed up on EduRev. Have you? |
Similar CAT Doubts
Question Description
How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? for CAT 2023 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for CAT 2023 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer?.
How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? for CAT 2023 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for CAT 2023 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer?.
Solutions for How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT.
Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free.
Here you can find the meaning of How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer?, a detailed solution for How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice How many sets of three distinct factors of the number N = 26 x 34 x 52 can be made such that the factors in each set have a highest common factor of 1 with respect to every other factor in that set?a)236b)360c)104d)380Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice CAT tests.
Do you know? How Toppers prepare for CAT Exam
With help of the best CAT teachers & toppers, We have prepared a guide for student who are
preparing for CAT : 15 Steps to clear CAT Exam
Download free EduRev App
Track your progress, build streaks, highlight & save important lessons and more!
(Scan QR code)
|
|
N = 26 × 34 × 52Case: [A]when none of the elements is 1 ⇒ the three factors must be some powers of 2, 3, 5 respectively.⇒ total number of such sets = 6 × 4 × 2 = 48Case: [B]when one of the elements is 1⇒ the other two factors could be of the form (2a), (3b) − number of sets = 6 × 4 = 24(26), (52) − number of sets = 6 × 2 = 12(34),(52) − number of sets = 4 × 2 = 8(26 × 34 × 52) − number of sets = 6 × 4 × 2 = 48(26 × 52 × 34) − number of sets = 6 × 2 × 4 = 48(34 × 52 × 26) − number of sets = 4 × 2 × 6 = 48∴ total number of such sets = 188combining both the cases, total sets possible= 188 + 48 = 236
|
© EduRev
|
Education Revolution
|
Follow Us
|
