Find all the values of p, such that 6 lies s...
Find all the values of p, such that 6 lies some where between the roots of the equation
x2 + 2(p - 3)x + 9 = 0. (‘x’ is a real number).
• a)
p < />
• b)
P > 6
• c)
0 < p="" />< />
• d)
0 < p="" />< />
Find all the values of p, such that 6 lies some where between the roo...
Both the roots will be real as 6 lies between the roots
(i) b2 − 4ac > 0
= 4(p − 3)2 − 4 × 9 > 0P(P − 6) > 0
p > 6 or p < />
(ii), since x = 6 lies between the two roots.
so, (6)2 + 2(p − 3)6 + 9 < /> Hence the correct option is A.
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Find all the values of p, such that 6 lies some where between the roots of the equationx2 + 2(p - 3)x + 9 = 0. (‘x’ is a real number).a)p b)P > 6c)0 d)0 Correct answer is option 'A'. Can you explain this answer?
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