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In the conversion of limestone to lime, CaCO3(s) ⇌ CaO(s) + CO2(g), the values of ΔH0 and ΔS0 are +179.1kJ mol-1 and 160.2 J/K, respectively, at 298 K and 1 bar. Assuming that H0 and ΔS0 do not change with temperature, the temperature above which conversion of limestone to lime will be spontaneous is
  • a)
    1008 K
  • b)
    1200 K
  • c)
    845 K
  • d)
    1118 K
Correct answer is option 'D'. Can you explain this answer?
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To determine the temperature above which the conversion of limestone to lime will be spontaneous, we can use the Gibbs free energy equation:

ΔG = ΔH - TΔS

where ΔG is the change in Gibbs free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.

Since we want to find the temperature above which the conversion is spontaneous, we need to find the temperature at which ΔG is negative.

Given information:
ΔH0 = 179.1 kJ mol-1 (convert to J mol-1)
ΔS0 = 160.2 J/K
T = 298 K

Converting ΔH0 to J mol-1:
ΔH0 = 179.1 kJ mol-1 = 179.1 × 10^3 J mol-1

Calculating ΔG at 298 K:
ΔG = ΔH - TΔS
ΔG = (179.1 × 10^3 J mol-1) - (298 K × 160.2 J/K)
ΔG = 179.1 × 10^3 J mol-1 - 47.7 × 10^3 J mol-1
ΔG = 131.4 × 10^3 J mol-1

Since ΔG is positive at 298 K, the conversion of limestone to lime is not spontaneous at this temperature.

To find the temperature at which ΔG becomes negative, we can set ΔG equal to zero and solve for T:

0 = ΔH - TΔS
TΔS = ΔH
T = ΔH/ΔS

Calculating the temperature using the given values:
T = (179.1 × 10^3 J mol-1)/(160.2 J/K)
T = 1118 K

Therefore, the temperature above which the conversion of limestone to lime will be spontaneous is 1118 K. The correct answer is option D.
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In the conversion of limestone to lime, CaCO3(s) ⇌ CaO(s) + CO2(g), the values of ΔH0 and ΔS0 are +179.1kJ mol-1 and 160.2 J/K, respectively, at 298 K and 1 bar. Assuming that H0 and ΔS0 do not change with temperature, the temperature above which conversion of limestone to lime will be spontaneous isa)1008 Kb)1200 Kc)845 Kd)1118 KCorrect answer is option 'D'. Can you explain this answer?
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In the conversion of limestone to lime, CaCO3(s) ⇌ CaO(s) + CO2(g), the values of ΔH0 and ΔS0 are +179.1kJ mol-1 and 160.2 J/K, respectively, at 298 K and 1 bar. Assuming that H0 and ΔS0 do not change with temperature, the temperature above which conversion of limestone to lime will be spontaneous isa)1008 Kb)1200 Kc)845 Kd)1118 KCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In the conversion of limestone to lime, CaCO3(s) ⇌ CaO(s) + CO2(g), the values of ΔH0 and ΔS0 are +179.1kJ mol-1 and 160.2 J/K, respectively, at 298 K and 1 bar. Assuming that H0 and ΔS0 do not change with temperature, the temperature above which conversion of limestone to lime will be spontaneous isa)1008 Kb)1200 Kc)845 Kd)1118 KCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the conversion of limestone to lime, CaCO3(s) ⇌ CaO(s) + CO2(g), the values of ΔH0 and ΔS0 are +179.1kJ mol-1 and 160.2 J/K, respectively, at 298 K and 1 bar. Assuming that H0 and ΔS0 do not change with temperature, the temperature above which conversion of limestone to lime will be spontaneous isa)1008 Kb)1200 Kc)845 Kd)1118 KCorrect answer is option 'D'. Can you explain this answer?.
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