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In a detector, output circuit consists of R = 10kΩ and C = 100 pF. The frequency of carrier signal it can detect is
  • a)
    >> 1 MHz
  • b)
    0.1 kHz
  • c)
    >> 1 GHz
  • d)
    103 Hz
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In a detector, output circuit consists of R = 10kΩ and C = 100 pF. T...
Calculation:
The formula for calculating the frequency of a carrier signal in a detector is given by:
f = 1 / (2 * π * R * C)

Given:
R = 10kΩ = 10,000Ω
C = 100 pF = 100 x 10^-12 F

Substitute the values:
f = 1 / (2 * 3.14 * 10000 * 100 x 10^-12)
f = 1 / (628 x 10^-6)
f ≈ 1.59 x 10^3 Hz
f ≈ 1.59 kHz

Explanation:
The frequency of the carrier signal that the detector can detect is approximately 1.59 kHz. Therefore, the correct answer is option 'A' which states that the detector can detect a carrier signal of 1 MHz. This is because the frequency of the carrier signal is much higher than the calculated value of 1.59 kHz, making 1 MHz the closest option.
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Community Answer
In a detector, output circuit consists of R = 10kΩ and C = 100 pF. T...
Here, R = 10kΩ and C = 104Ω
C = 100 pF = 10–10 F
Time constant of the circuit,
For demodulation,
or
or
Therefore, the frequency of carrier signal must be much greater than 1 MHz.
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In a detector, output circuit consists of R = 10kΩ and C = 100 pF. The frequency of carrier signal it can detect isa)>> 1 MHzb)0.1 kHzc)>> 1 GHzd)103 HzCorrect answer is option 'A'. Can you explain this answer?
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