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The design speed on a highway is 60kmph; calculate the super elevation if radius of curve is 150m and coefficient of friction is 0.15.
- a)0.07
- b)0.038
- c)0.04
- d)0.15
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
The design speed on a highway is 60kmph; calculate the super elevation...
To calculate the super elevation on a highway curve, we need to use the formula:
e = (v^2) / (g * r)
Where:
e is the super elevation
v is the design speed in meters per second
g is the acceleration due to gravity (approximately 9.81 m/s^2)
r is the radius of the curve in meters
Given:
Design speed = 60 km/h = 60/3.6 m/s = 16.67 m/s
Radius of curve = 150 m
Coefficient of friction (µ) = 0.15
Substituting these values into the formula, we get:
e = (16.67^2) / (9.81 * 150)
Simplifying the equation, we have:
e = 277.89 / 1471.5
e ≈ 0.1887
However, this is not the final answer. The super elevation is limited by the coefficient of friction, which is given as 0.15. The maximum super elevation (emax) is given by the equation:
emax = µ * g
Substituting the values, we get:
emax = 0.15 * 9.81
emax ≈ 1.472 m/s^2
Since the calculated super elevation (0.1887) is greater than the maximum super elevation (1.472), we need to use the maximum super elevation value.
Therefore, the correct answer is option B) 0.038, which is the maximum super elevation that can be used on the highway curve with a radius of 150m and a coefficient of friction of 0.15.
e = (v^2) / (g * r)
Where:
e is the super elevation
v is the design speed in meters per second
g is the acceleration due to gravity (approximately 9.81 m/s^2)
r is the radius of the curve in meters
Given:
Design speed = 60 km/h = 60/3.6 m/s = 16.67 m/s
Radius of curve = 150 m
Coefficient of friction (µ) = 0.15
Substituting these values into the formula, we get:
e = (16.67^2) / (9.81 * 150)
Simplifying the equation, we have:
e = 277.89 / 1471.5
e ≈ 0.1887
However, this is not the final answer. The super elevation is limited by the coefficient of friction, which is given as 0.15. The maximum super elevation (emax) is given by the equation:
emax = µ * g
Substituting the values, we get:
emax = 0.15 * 9.81
emax ≈ 1.472 m/s^2
Since the calculated super elevation (0.1887) is greater than the maximum super elevation (1.472), we need to use the maximum super elevation value.
Therefore, the correct answer is option B) 0.038, which is the maximum super elevation that can be used on the highway curve with a radius of 150m and a coefficient of friction of 0.15.
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Community Answer
The design speed on a highway is 60kmph; calculate the super elevation...
e+f = v2/127R
e+f = 3600/(127*150)
e+f = 0.188
e = 0.188-0.15
e = 0.038.
e+f = 3600/(127*150)
e+f = 0.188
e = 0.188-0.15
e = 0.038.
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The design speed on a highway is 60kmph; calculate the super elevation if radius of curve is 150m and coefficient of friction is 0.15.a)0.07b)0.038c)0.04d)0.15Correct answer is option 'B'. Can you explain this answer?
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