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Consider a beam of width 300 mm, effective depth 450 mm, VuVu = 280 kN, M1M1 = 200 kNm, τbdτbd = 1.2 N/mm2. The maximum diameter (in mm) of the deformed bar going into the support of simply supported beam. (Assume end confinement without any anchorage length). Take Fe 415.a)19b)20Correct answer is between '19,20'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Consider a beam of width 300 mm, effective depth 450 mm, VuVu = 280 kN, M1M1 = 200 kNm, τbdτbd = 1.2 N/mm2. The maximum diameter (in mm) of the deformed bar going into the support of simply supported beam. (Assume end confinement without any anchorage length). Take Fe 415.a)19b)20Correct answer is between '19,20'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a beam of width 300 mm, effective depth 450 mm, VuVu = 280 kN, M1M1 = 200 kNm, τbdτbd = 1.2 N/mm2. The maximum diameter (in mm) of the deformed bar going into the support of simply supported beam. (Assume end confinement without any anchorage length). Take Fe 415.a)19b)20Correct answer is between '19,20'. Can you explain this answer?.

Solutions for Consider a beam of width 300 mm, effective depth 450 mm, VuVu = 280 kN, M1M1 = 200 kNm, τbdτbd = 1.2 N/mm2. The maximum diameter (in mm) of the deformed bar going into the support of simply supported beam. (Assume end confinement without any anchorage length). Take Fe 415.a)19b)20Correct answer is between '19,20'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.

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