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Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5 m.
(In Integers)
Correct answer is '3'. Can you explain this answer?
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Most Upvoted Answer
Sodium light of wavelengths 650 nm and 655 nm is used to study diffrac...
To solve this problem, we can use the formula for the angular position of the first maximum in a single-slit diffraction pattern:
sinθ = mλ / a
where
θ is the angle between the central maximum and the first maximum,
m is the order of the maximum (1 for the first maximum),
λ is the wavelength of light,
and a is the width of the slit.
We can rearrange this formula to solve for the distance between the positions of the first maxima (Δx) for two different wavelengths:
Δx = (λ2 / a) - (λ1 / a)
Given that the wavelengths are 650 nm and 655 nm, and the slit width is 0.5 mm (or 0.0005 m), we can substitute these values into the formula to find Δx:
Δx = (655 nm / 0.0005 m) - (650 nm / 0.0005 m)
= (655 × 10^-9 m) / (0.0005 m) - (650 × 10^-9 m) / (0.0005 m)
= (1.31 × 10^-3 m) - (1.3 × 10^-3 m)
= 0.01 × 10^-3 m
= 10 × 10^-6 m
= 10 μm
Therefore, the separation between the positions of the first maxima of the diffraction pattern obtained in the two cases is 10 μm.
sinθ = mλ / a
where
θ is the angle between the central maximum and the first maximum,
m is the order of the maximum (1 for the first maximum),
λ is the wavelength of light,
and a is the width of the slit.
We can rearrange this formula to solve for the distance between the positions of the first maxima (Δx) for two different wavelengths:
Δx = (λ2 / a) - (λ1 / a)
Given that the wavelengths are 650 nm and 655 nm, and the slit width is 0.5 mm (or 0.0005 m), we can substitute these values into the formula to find Δx:
Δx = (655 nm / 0.0005 m) - (650 nm / 0.0005 m)
= (655 × 10^-9 m) / (0.0005 m) - (650 × 10^-9 m) / (0.0005 m)
= (1.31 × 10^-3 m) - (1.3 × 10^-3 m)
= 0.01 × 10^-3 m
= 10 × 10^-6 m
= 10 μm
Therefore, the separation between the positions of the first maxima of the diffraction pattern obtained in the two cases is 10 μm.
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Community Answer
Sodium light of wavelengths 650 nm and 655 nm is used to study diffrac...
The position of the 1st maxima is 
.
⇒ According to the given values,
Required separation = 3/2 × (655 nm - 650 nm) × 2m / 0.5 mm
= 3 × 10-5 m
.⇒ According to the given values,
Required separation = 3/2 × (655 nm - 650 nm) × 2m / 0.5 mm
= 3 × 10-5 m
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Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5m.(In Integers)Correct answer is '3'. Can you explain this answer?
Question Description
Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5m.(In Integers)Correct answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5m.(In Integers)Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5m.(In Integers)Correct answer is '3'. Can you explain this answer?.
Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5m.(In Integers)Correct answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5m.(In Integers)Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5m.(In Integers)Correct answer is '3'. Can you explain this answer?.
Solutions for Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is _____ × 10-5m.(In Integers)Correct answer is '3'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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