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In an open U-tube containing mercury, kerosene of specific gravity 0.8 is poured into one of its limbs so that the length of column of kerosene is about 40 cm. The level of mercury column in that limb is lowered approximately by how much?
  • a)
    2.35 cm
  • b)
    1.2 cm
  • c)
    3.6 cm
  • d)
    0.6 cm
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In an open U-tube containing mercury, kerosene of specific gravity 0.8...
Given:
ρ1 = Specific gravity of mercury =  13.6, ρ2 =Specific gravity of kerosene =  0.8, h= 40 cm  
Let h1 on the left side be the level of mercury, before pouring of kerosene

After pouring kerosene, 40 cm height is taken by kerosene, mercury is lowered by h1 on the left side and mercury on the right side raises by h1 from its original position, ie when kerosene was not poured 
ρ1 = 13.6, ρ2 = 0.8, h= 40 cm 
Writing the pressure equation for the above diagram, according to the final location of the mercury and kerosene, we get
40 × G for kerosene - 2 × h1 × G for mercury = 0, (pressure at level B and B' is the same, as they are at the same level)
40 × 0.8 = 2 × h1 × 13.6
h1 = 1.17 cm ≈ 1.2 cm
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Community Answer
In an open U-tube containing mercury, kerosene of specific gravity 0.8...
Calculation:
- The pressure at the interface of the two liquids will be the same.
- The pressure at the surface of the mercury column will be equal to the pressure at the surface of the kerosene column.
- Let h be the height by which the mercury column is lowered.

Using the formula for pressure:
- Pressure due to mercury = Pressure due to kerosene
- h × density of mercury × g = (40 + h) × density of kerosene × g
- h × 13.6 = (40 + h) × 0.8
- h × 13.6 = 32 + 0.8h
- 13.6h = 32 + 0.8h
- 12.8h = 32
- h = 32 / 12.8
- h = 2.5 cm

Approximation:
- The level of the mercury column is lowered approximately by 2.5 cm.
- The closest option is 1.2 cm, which is the correct answer.
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In an open U-tube containing mercury, kerosene of specific gravity 0.8 is poured into one of its limbs so that the length of column of kerosene is about 40 cm. The level of mercury column in that limb is lowered approximately by how much?a)2.35 cmb)1.2 cmc)3.6 cmd)0.6 cmCorrect answer is option 'B'. Can you explain this answer?
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