Find the smallest square number which is exactly divisible by 10 12 an...
Smallest Square Number Divisible by 10, 12, and 25
In order to find the smallest square number that is exactly divisible by 10, 12, and 25, we need to follow these steps:
Step 1: Prime Factorization
We need to find the prime factors of each of the given numbers:
- 10 = 2 x 5
- 12 = 2 x 2 x 3
- 25 = 5 x 5
Step 2: Identify the Common Factors
We need to identify the factors that are common to all three numbers. In this case, the only common factor is 5, so we need to ensure that the square number we find is divisible by 5.
Step 3: Find the LCM of the Remaining Factors
Next, we need to find the LCM of the remaining factors, which are 2 and 3. The LCM of 2 and 3 is 6.
Step 4: Multiply the Common Factor with the LCM
Finally, we need to multiply the common factor (5) with the LCM (6) to get the smallest square number that is exactly divisible by 10, 12, and 25:
5 x 6 = 30
Step 5: Find the Square of the Number
Now, we need to find the square of the number we just found:
30 x 30 = 900
Step 6: Verify the Answer
We can verify that 900 is the smallest square number that is exactly divisible by 10, 12, and 25 by checking that:
- 900 is divisible by 10 (since it ends in a 0)
- 900 is divisible by 12 (since it is divisible by 2 and 3)
- 900 is divisible by 25 (since it ends in two 0's)
Therefore, the smallest square number that is exactly divisible by 10, 12, and 25 is 900.