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Compound X on reaction with O3 followed by Zn/ H2O gives formaldehyde and 2-methyl propanal as products. The compound X is :
- a)2-Methylbut-l-ene
- b)2-Methylbut-2-ene
- c)Pent-2-ene
- d)3-Methylbut-l-ene
Correct answer is option 'D'. Can you explain this answer?
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Compound X on reaction with O3 followed by Zn/ H2O gives formaldehyde ...
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Compound X on reaction with O3 followed by Zn/ H2O gives formaldehyde ...
Reaction:
Compound X + O3 → Formaldehyde + 2-Methylpropanal
Reducing Agent:
Zn/H2O
Product Formation:
The given reaction involves the ozonolysis of compound X followed by treatment with Zn/H2O to produce formaldehyde and 2-methylpropanal as products. Let's analyze the given options to determine the compound X.
Option A: 2-Methylbut-1-ene
If compound X is 2-methylbut-1-ene, the ozonolysis of this compound would result in the formation of 2-methylpropanal as the major product and formaldehyde as the minor product. However, the question states that formaldehyde is one of the products, which contradicts this option. Therefore, option A is incorrect.
Option B: 2-Methylbut-2-ene
If compound X is 2-methylbut-2-ene, the ozonolysis of this compound would result in the formation of 2-methylpropanal as the major product and formaldehyde as the minor product. This aligns with the given reaction. However, we need to consider the reducing agent, Zn/H2O. Zn/H2O is not capable of reducing a double bond present at the 2-position of a compound. Therefore, option B is incorrect.
Option C: Pent-2-ene
If compound X is pent-2-ene, the ozonolysis of this compound would result in the formation of pentanal and formaldehyde as products. This does not align with the given reaction. Therefore, option C is incorrect.
Option D: 3-Methylbut-1-ene
If compound X is 3-methylbut-1-ene, the ozonolysis of this compound would result in the formation of formaldehyde and 2-methylpropanal as products. This aligns with the given reaction. Additionally, Zn/H2O is capable of reducing the double bond present at the 1-position of the compound, which is required in the given reaction. Therefore, option D is the correct answer.
Conclusion:
Based on the given reaction and the reducing agent used, compound X is 3-methylbut-1-ene (option D).
Compound X + O3 → Formaldehyde + 2-Methylpropanal
Reducing Agent:
Zn/H2O
Product Formation:
The given reaction involves the ozonolysis of compound X followed by treatment with Zn/H2O to produce formaldehyde and 2-methylpropanal as products. Let's analyze the given options to determine the compound X.
Option A: 2-Methylbut-1-ene
If compound X is 2-methylbut-1-ene, the ozonolysis of this compound would result in the formation of 2-methylpropanal as the major product and formaldehyde as the minor product. However, the question states that formaldehyde is one of the products, which contradicts this option. Therefore, option A is incorrect.
Option B: 2-Methylbut-2-ene
If compound X is 2-methylbut-2-ene, the ozonolysis of this compound would result in the formation of 2-methylpropanal as the major product and formaldehyde as the minor product. This aligns with the given reaction. However, we need to consider the reducing agent, Zn/H2O. Zn/H2O is not capable of reducing a double bond present at the 2-position of a compound. Therefore, option B is incorrect.
Option C: Pent-2-ene
If compound X is pent-2-ene, the ozonolysis of this compound would result in the formation of pentanal and formaldehyde as products. This does not align with the given reaction. Therefore, option C is incorrect.
Option D: 3-Methylbut-1-ene
If compound X is 3-methylbut-1-ene, the ozonolysis of this compound would result in the formation of formaldehyde and 2-methylpropanal as products. This aligns with the given reaction. Additionally, Zn/H2O is capable of reducing the double bond present at the 1-position of the compound, which is required in the given reaction. Therefore, option D is the correct answer.
Conclusion:
Based on the given reaction and the reducing agent used, compound X is 3-methylbut-1-ene (option D).
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Compound X on reaction with O3 followed by Zn/ H2O gives formaldehyde and 2-methyl propanal as products. The compound X is :a)2-Methylbut-l-eneb)2-Methylbut-2-enec)Pent-2-ened)3-Methylbut-l-eneCorrect answer is option 'D'. Can you explain this answer?
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