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To an ideal triatomic gas 800 cal heat energy is given at constant pressure. if vibrational mode is neglected then energy used by gas in work done against surroundings is (1) 200 cal (2) 300 cal (3) 400 cal (4) 60 cal?
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To an ideal triatomic gas 800 cal heat energy is given at constant pre...
Explanation:

Given:

Heat energy given to an ideal triatomic gas = 800 cal

Constant pressure = P

Vibrational mode is neglected

Work done by the gas:

The work done by the gas can be calculated using the formula:

W = PΔV

Where,

P = Pressure of the gas

ΔV = Change in volume of the gas

Change in internal energy:

The change in internal energy of the gas can be given by:

ΔU = Q - W

Where,

Q = Heat energy given to the gas

W = Work done by the gas

Calculations:

As the vibrational mode is neglected, the given heat energy will be used only to increase the kinetic energy of the gas molecules.

Therefore, the change in internal energy of the gas will be ΔU = 3/2 nRΔT, where n is the number of moles of the gas, R is the gas constant, and ΔT is the change in temperature of the gas.

Equating the above two equations, we get:

3/2 nRΔT = Q - PΔV

As the pressure is constant, the work done by the gas can be given by:

W = PΔV = nRΔT

Substituting the above equation in the previous equation, we get:

3/2 nRΔT = Q - nRΔT

ΔT = 800/(5/2 nR)

Work done by the gas:

W = nRΔT = 800/(5/2) = 320 cal

Answer:

The energy used by the gas in work done against surroundings is 320 cal (approx). Therefore, the correct option is (3) 400 cal.
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To an ideal triatomic gas 800 cal heat energy is given at constant pressure. if vibrational mode is neglected then energy used by gas in work done against surroundings is (1) 200 cal (2) 300 cal (3) 400 cal (4) 60 cal?
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