To an ideal triatomic gas 800 cal heat energy is given at constant pre...
Explanation:
Given:
Heat energy given to an ideal triatomic gas = 800 cal
Constant pressure = P
Vibrational mode is neglected
Work done by the gas:
The work done by the gas can be calculated using the formula:
W = PΔV
Where,
P = Pressure of the gas
ΔV = Change in volume of the gas
Change in internal energy:
The change in internal energy of the gas can be given by:
ΔU = Q - W
Where,
Q = Heat energy given to the gas
W = Work done by the gas
Calculations:
As the vibrational mode is neglected, the given heat energy will be used only to increase the kinetic energy of the gas molecules.
Therefore, the change in internal energy of the gas will be ΔU = 3/2 nRΔT, where n is the number of moles of the gas, R is the gas constant, and ΔT is the change in temperature of the gas.
Equating the above two equations, we get:
3/2 nRΔT = Q - PΔV
As the pressure is constant, the work done by the gas can be given by:
W = PΔV = nRΔT
Substituting the above equation in the previous equation, we get:
3/2 nRΔT = Q - nRΔT
ΔT = 800/(5/2 nR)
Work done by the gas:
W = nRΔT = 800/(5/2) = 320 cal
Answer:
The energy used by the gas in work done against surroundings is 320 cal (approx). Therefore, the correct option is (3) 400 cal.