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A man has 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in all and the total amount is 160. If there are thrice as many 1 Rupee coins as there are 25 paise coins, then what is the number of 50 paise coins?
  • a)
    60
  • b)
    120
  • c)
    40
  • d)
    80
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A man has 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in...
Given:
Total coin = 220
Total money = Rs. 160
There are thrice as many 1 Rupee coins as there are 25 paise coins.
Concept used:
Ratio method is used.
Calculation:
Let the 25 paise coins be 'x'
So, one rupees coins = 3x
50 paise coins = 220 – x – (3x) = 220 – (4x)
According to the questions,
3x + [(220 – 4x)/2] + x/4 =160
⇒ (12x + 440 – 8x + x)/4 = 160
⇒  5x + 440 = 640
⇒ 5x = 200
⇒ x = 40
So, 50 paise coins = 220 – (4x) = 220 – (4 × 40) = 60
∴ The number of 50 paise coin is 60.
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Community Answer
A man has 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in...
Let's break down the information given in the question:

- The man has 25 paise, 50 paise, and 1 Rupee coins.
- There are a total of 220 coins.
- The total amount of all the coins is 160.
- The number of 1 Rupee coins is three times the number of 25 paise coins.

To solve this problem, we can set up a system of equations. Let's denote the number of 25 paise coins as x, the number of 50 paise coins as y, and the number of 1 Rupee coins as z.

1. Total number of coins equation:
The sum of the number of 25 paise, 50 paise, and 1 Rupee coins is equal to 220:
x + y + z = 220

2. Total value equation:
The sum of the values of all the coins is equal to 160:
(25/100)x + (50/100)y + (1/1)z = 160
0.25x + 0.5y + z = 160

3. Relationship between 1 Rupee and 25 paise coins:
The number of 1 Rupee coins is three times the number of 25 paise coins:
z = 3x

Now, we have a system of three equations with three variables. We can solve this system to find the values of x, y, and z.

First, substitute z = 3x into the total number of coins equation:
x + y + 3x = 220
4x + y = 220

Next, substitute z = 3x into the total value equation:
0.25x + 0.5y + 3x = 160
3.25x + 0.5y = 160

Now we have two equations with two variables. We can solve this system using any method, such as substitution or elimination. Let's solve it using elimination:

Multiply the first equation by 0.5 to make the coefficients of y in both equations equal:
2x + 0.5y = 110

Subtract this equation from the second equation:
3.25x + 0.5y - (2x + 0.5y) = 160 - 110
1.25x = 50
x = 40

Substitute the value of x back into the first equation:
4(40) + y = 220
y = 60

So, there are 60 50 paise coins.

Therefore, the correct answer is option A) 60.
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Question Description
A man has 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in all and the total amount is 160. If there are thrice as many 1 Rupee coins as there are 25 paise coins, then what is the number of 50 paise coins?a)60b)120c)40d)80Correct answer is option 'A'. Can you explain this answer? for SAT 2026 is part of SAT preparation. The Question and answers have been prepared according to the SAT exam syllabus. Information about A man has 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in all and the total amount is 160. If there are thrice as many 1 Rupee coins as there are 25 paise coins, then what is the number of 50 paise coins?a)60b)120c)40d)80Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for SAT 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man has 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in all and the total amount is 160. If there are thrice as many 1 Rupee coins as there are 25 paise coins, then what is the number of 50 paise coins?a)60b)120c)40d)80Correct answer is option 'A'. Can you explain this answer?.
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