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The most suitable reagent for the following conversation is
- a)LiBH4 in THF
- b)NaBH4, CeCl3. 7H2O, EtOH
- c)Zn(BH4)2, DME
- d)LiAlH(OEt)3, THF
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The most suitable reagent for the following conversation isa)LiBH4in T...
The reducing abilities of hydride donors can vary widely depending on the nature of the metal center and any accompanying ligands or counter ions. Let's compare the given reagents:
- LiBH4 (Lithium Borohydride): This is a strong reducing agent and can reduce esters, carboxylic acids, aldehydes, and ketones to alcohols. It can also reduce amides to amines. However, its use is somewhat limited by its reactivity with protic solvents, which can decompose the reagent.
- NaBH4 (Sodium Borohydride): Sodium borohydride is less reactive than lithium borohydride and is typically used for the reduction of aldehydes and ketones to alcohols. In general, it doesn't effectively reduce esters, carboxylic acids, or amides under standard conditions.
- LiAlH(OEt)3 (Lithium Triethoxyaluminum Hydride): This is a less reactive but more selective reducing agent compared to LAH and can reduce esters, carboxylic acids, and amides to alcohols without reducing more reactive functional groups like ketones and aldehydes.
- Zn(BH4)2 (Zinc Borohydride): This is a strong reducing agent similar to LiBH4 in reactivity and can reduce a variety of carbonyl containing functional groups like esters, carboxylic acids, aldehydes, and ketones.
So, in terms of general reactivity, one might rank the reducing agents as follows:
Zn(BH4)2 > LiBH4 > LiAlH(OEt)3 > NaBH4
Zn(BH4)2 > LiBH4 > LiAlH(OEt)3 > NaBH4
- [BH4]- will attack from below the plane steric hindrance from above the plane
- The oxide form will abstract the proton from the solvent and become a Hydroxy group.
So, The most suitable reagent for the following conversation is will be Zn(BH4)2.
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The most suitable reagent for the following conversation isa)LiBH4in THFb)NaBH4, CeCl3. 7H2O, EtOHc)Zn(BH4)2, DMEd)LiAlH(OEt)3, THFCorrect answer is option 'C'. Can you explain this answer?
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The most suitable reagent for the following conversation isa)LiBH4in THFb)NaBH4, CeCl3. 7H2O, EtOHc)Zn(BH4)2, DMEd)LiAlH(OEt)3, THFCorrect answer is option 'C'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The most suitable reagent for the following conversation isa)LiBH4in THFb)NaBH4, CeCl3. 7H2O, EtOHc)Zn(BH4)2, DMEd)LiAlH(OEt)3, THFCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The most suitable reagent for the following conversation isa)LiBH4in THFb)NaBH4, CeCl3. 7H2O, EtOHc)Zn(BH4)2, DMEd)LiAlH(OEt)3, THFCorrect answer is option 'C'. Can you explain this answer?.
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